in which reaction does nitrogen exhibit variation of Oxidation State from - 3 to + 5??
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the reaction is given in the figure
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Since, the Nitrogen is that substance which is having a very small difference in its np and ns orbitals So, the reaction in which the NH3 or the ammonia is converted to the N2O5 or the di-nitrogen pentaoxide. The oxidation number of the nitrogen or N gets oxidized from -3 to +5 in the above reaction.
For the NH3 we get that N + 3(+1)=0 which on solving we will get N = -3. While for the N2O5 we will get 2N + 5(-2)=0 which on solving we will get that N= +5. So, from -3 to +5 oxidation occurs.
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