Question

In which reaction, hybridisation of underlined atom remains unchanged? (1) Combustion of CH 4 (2) Solidification of PCI, vapour (3) SF, vapour is passed through liq. HF (4) Al(OH), ppt. dissolves in NaOH​

Answer 1

Answer:

${ph}^{3} + {h}^{ + } = {ph4}^{ + }$

Explanation:

The hybridization of P remains the same, i.e., sp3 hybridization. In PH3, P atom contains 3 bond pairs of electrons and one lone pair of electrons.

In PH4+, P atom contains 4 bond pairs of electrons.