Question

in which term of Ap 2, 13,24 - - - ; 321​

Answer 1

Answer:

30th term

Step-by-step explanation:

Tn=a+(n-1)*d

321=2*(n-1)*11

321=2+11n-11

11n=321+9

11n=330

n=330/11

n=30

Answer 2

Answer:

a = 2

d = 13 - 2

= 11

n = ?

a(n) = a + ( n - 1) d

321 = 2 + (n - 1) 11

321 - 2 = ( n - 1) 11

319 = (n -1 ) 11

319 ÷ 11 = ( n - 1 )

29 = n - 1

29 + 1 = n

30 = n

Therefore, the 30th term of this A.P is 321.