Question

In which value of K,x=2/3 is a solution of equation Kx^2-x-2=0.
please solve in full step.

Answer 1

Hey user here is your answer....

x=2/3

---> Given equation- kx^2-x-2

◆ k(2/3)^2-(2/3)-2=0

◆k(4/9)-(2/3)-2=0
◆4k/9-2/3-2

◆Take L.C.M

4K-6-18/9=0

◆4K-24=0
◆4K=24
◆K=24/4

◆K=6


HOPE it helps you☺️

Answer 2

put x= 2/3 in the following equation, we get

k× (2/3)2 - 2/3 - 2 = 0
4/9k - 2/3 - 2 = 0
4/9k - 8/3 = 0
4/9k = 8/3
k/3 = 2
k = 6

hope it helps u..☺☺