Question

in which way is a displacement reaction different from a double displacement reaction? explain with two suitable examples​

Answer 1

Answer:

import java.util.Scanner;

public class KboatEvenSuccessor

{

public void computeProduct() {

Scanner in = new Scanner(System.in);

System.out.print("Enter the number: ");

int num = in.nextInt();

int orgNum = num;

int prod = 1;

while (num != 0) {

int digit = num % 10;

num /= 10;

if (digit % 2 == 0)

prod = prod * (digit + 1);

}

if (prod == 1)

System.out.println("No even digits in " + orgNum);

else

System.out.println("Product of even digits successors is "

+ prod);

}

}

What is the question of this programming?

Answer 2

Answer:

In displacement reaction the more reactive element displaces the less reactive element from its compound.

In double displacement reaction two elements interchange their radicles

Displacement reaction = Zn + FeSO4=ZnSO4+Fe

Double = AgNO3 + NaCl → AgCl + NaNO3

Explanation: