in write nearest number to 123 ,which is exactly divisible by 5
Answers
Answer:
125
Step-by-step explanation:
numbers that end with 5,0 is divisible by 5
125÷5=25
thus 125 is the number
pls mark as branliest
Given :- write nearest number to 123 ,which is exactly divisible by 5 ?
Answer :-
Let nearest number to 123 is x which is exactly divisible by 5 .
so,
→ either will will be smaller than 123 123 > x .
or,
→ greater than 123 < x .
checking both now,
Smaller than 123 :-
→ 123 - 1 = 122 / 5 ≠ Remainder 0 .
→ 123 - 2 = 121 / 5 ≠ Remainder 0 .
→ 123 - 1 = 120 / 5 = Remainder 0 .
we gets, x = 120 .
now, checking greater number ,
→ 123 + 1 = 124 / 5 ≠ Remainder 0 .
→ 123 + 2 = 125 / 5 = Remainder 0 .
we gets, x = 125 .
since, 120 < 123 < 125
→ 123 - 120 = 3 numbers far
→ 125 - 123 = 2 numbers far .
therefore, we can conclude that, 125 is the nearest number to 123 that is exactly divisible by 5 .
Learn more :-
(7sqrt(3))/(sqrt(10+sqrt(3)))-(2sqrt(5))/(sqrt(6)+sqrt(5))-(3sqrt(2))/(sqrt(5)+3sqrt(2))
https://brainly.in/question/32043164
if the positive square root of (√190 +√ 80) i multiplied by (√2-1) and the
product is raised to the power of four the re...
https://brainly.in/question/26618255