Math, asked by hemanthreddy17, 12 hours ago

in write nearest number to 123 ,which is exactly divisible by 5​

Answers

Answered by netraRamesh
1

Answer:

125

Step-by-step explanation:

numbers that end with 5,0 is divisible by 5

125÷5=25

thus 125 is the number

pls mark as branliest

Answered by RvChaudharY50
0

Given :- write nearest number to 123 ,which is exactly divisible by 5 ?

Answer :-

Let nearest number to 123 is x which is exactly divisible by 5 .

so,

→ either will will be smaller than 123 123 > x .

or,

→ greater than 123 < x .

checking both now,

Smaller than 123 :-

→ 123 - 1 = 122 / 5 ≠ Remainder 0 .

→ 123 - 2 = 121 / 5 ≠ Remainder 0 .

→ 123 - 1 = 120 / 5 = Remainder 0 .

we gets, x = 120 .

now, checking greater number ,

→ 123 + 1 = 124 / 5 ≠ Remainder 0 .

→ 123 + 2 = 125 / 5 = Remainder 0 .

we gets, x = 125 .

since, 120 < 123 < 125

→ 123 - 120 = 3 numbers far

→ 125 - 123 = 2 numbers far .

therefore, we can conclude that, 125 is the nearest number to 123 that is exactly divisible by 5 .

Learn more :-

(7sqrt(3))/(sqrt(10+sqrt(3)))-(2sqrt(5))/(sqrt(6)+sqrt(5))-(3sqrt(2))/(sqrt(5)+3sqrt(2))

https://brainly.in/question/32043164

if the positive square root of (√190 +√ 80) i multiplied by (√2-1) and the

product is raised to the power of four the re...

https://brainly.in/question/26618255

Similar questions