Question

In (x+2)(x-5) = 0 , the value of a, b and c are

Answer 1

Answer:

Consider, x

2

+3x+5=0

a=1 , b=3 , c=5

Let p,q be the two roots. Now, by Vieta's formulas,

p+q=−3=−ba and pq=5=ca

Therefore, b=3a, c=5a. Hence, a+b+c = a+3a+5a = 9a. But given that a,b,cϵN.

∴ The minimum value of a+b+c=9

Step-by-step explanation:

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