History, asked by spicysuriya24, 4 months ago

In
X(m)
6
the figure given below, the position-time graph
of a particle of mass 0.1 kg is shown. The impulse
at 1-2 sec is
(1) 0.2 kg-m/s
(2) -O-2 kg-m/s
(3) 0.1 kg-m/s
(4) -0.4 kg-m/s
4
2+
2 4
t(seconds)
6​

Answers

Answered by PureHoneyLove
20

Impulse =mu-mv=−(0.1×24−m×0[v = 0) after two seconds]=−0.2kg m sec−1

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