In x ray tube if filament voltage is increased by 50 and x ray tube voltage is increased by 100 then cut off wavenlength
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Utilising the Duane–Hunt law you can determine the minimal wavelength of emitted x-rays, using the following formula:
λ=ℎ/
λ
m
i
n
=
h
c
/
e
V
Where h is Planck’s constant, c is speed of light and eV the applied potential (for this purpose, the same as KV).
So, in your case it would be:
λ=1.23984193/50=0.0247968386
λ
m
i
n
=
1.23984193
/
50
=
0.0247968386
p
m
But, as Cortland Richmond already wrote, the material of which the anode is a major part of what determines the wavelength of emitted x-rays.
Brain liest plz
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