Math, asked by rinkiwalia141, 2 months ago

In x (x + 1)2(x + 2) = 72, one of the imaginary root is​

Answers

Answered by irshadmodak
0

Answer:

x^2+3x-68

Step-by-step explanation:

x(x+1)2(x+2)=72

x*x+x*1 +2*x+2*2=72

x^2+x+2x+4=72

x^2+3x+4=72

x^2+3x=72-4

x^2+3x=68

x^2+3x-68

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