Question

In πx2/2 +x+10,the coefficient of X2 is
(a)π/2
(b)1
(c)-π/2
(d)-1​

Answer 1

Answer:

helo guys its your answer

Step-by-step explanation:

In πx2/2 +x+10,the coefficient of X2 is (a)π/2 (b)1 (c)-π/2 (d)-1. 1. See answer. Add Coefficient of x2 in ax2+bx+c =0 is a. Hence, coefficients of x2 in. (i) 2+x2+x is 1. (ii) 2−x2+x3 is −1. (iii) 2πx2+x is 2π.(i)6πx+x2−1(ii)3x−5(iii)(x−1)(3x−4)(iv)(2x −5)(2x2−3x+1). Share ... (i) Coefficient ofx2 in the following ... =4x2−6x2+2x−10x215x−5.

Answer 2

Answer:

4x2−6x2+2x−10x215x−5.