Question

 In XA there are 20 boys and 25 girls. In XB there are 20 girls and 20 boys . If one student is selected from each class. What is the probability that atleast one of them is a girl?​

Answer 1

Answer:

3/16

Step-by-step explanation:

Probability of selecting the girl from class 10A ,

P(GA) = 20/40 = 1/2

Probability of selecting the girl from class 10B ,

P(GB) = 15/40 = 3/8

Total probability of girl select from both class,

P(T) = P(GA) * P(GB)

P(T) = (1/2) * (3/8)

P(T) = 3/16.

Answer 2

Answer:

3/16

Step-by-step explanation:

that's the answer of your question.