Question

In xeo3 no of bond pairs pi bonds and lone pair is

Answer 1

To satisfy the valency of oxygen xenon will form double bond with each oxygen

And hence there are 3 bond pairs i,e 6 bonds out of which 3 are sigma and 3 are pi bond

There is one lone pair left on xenon out of 8 , 6are used for bond making

Thus hybridization of xe is 3+1=4 that is sp3.

So the geometry is distorted tetrahedron

and the shape is trigonal pyramidal

Answer 2

Answer:

XeO3 has three double bonds and each double bond has 1σ and 1π bonds.

Explanation:

• Xenon is a noble gas. It has a completely filled valence p shell and has 8 electrons in its valence shell.
• The valence shell electrons are excited to the empty d orbital and participate in bond formation.
• The number of bond pairs on the Xe atom is– 5
• The number of π-bonds on the Xe atom is– 3
• The number of lone pairs on the Xe atom is– 0
• XeO3 has three double bonds and each double bond has 1σ and 1π bonds.
• Hybridization, H = ½(V+X–C+A) = ½(8+0–0+0) = 4, So sp³ hybridized. So tetrahedral structure.
• No of lone pair = H–X–D = 4–0–3 = 1
• As lone pair is present the structure will be distorted tetrahedral and without the lone pair structure is pyramidal.
• H = hybridization no. (if 2 then sp, if 3 then sp² etc.)
• V = valence electrons of central atom.
• X = no. of monovalent atom.
• C = cationic charge. A = anionic charge.
• D = no. of divalent atom.
• Hence, total number of bonds are 3σ and 3π bonds.