Question

In XeOF⁴, let x be the total numbet of bond pairs around Xe, y be the total number of lone pairs and z be the total number of 90° OXeF angles, then x+y+z is ?​

Answer 1

Answer:

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Answer 2

Hey Miss

Here's The Answer

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XeOF₄

• Given :

• x is total BP around Xe
• y is total LP
• z is total 90° OXeF angles

• To Find :

• x + y + z = ?

• Solution :

• Clearly, Total number of bond around Xe is 6

=> Therefore, x = 6

• Total number of lone pair in XeOF₄

=> there are total 15 lone pairs, on XeOF₄ , therefore y = 15

• total 90° OXeF angles

=> All OXeF angles on XeOF₄ are 90° , therefore z = 4

• Hence

=> x + y + z

=> 6 + 15 + 4

=> 25

Hope It Helps ^^