Question

in xy plane find the distance of point (-3,4) from the origin​

Answer 1

Answer:

5 units

Explanation:

let the point on origin be P(0,0)

and let the given point be Q(-3,4)

by using distance formula

PQ=√(X2-X1)^2+(Y2-Y1)^2

PQ=√(-3-0)^2+(4-0)^2

PQ=√9+16

PQ=√25

PQ=5

therefore the distance of point (-3,4) from origin is 5 units