Question

In xyz,angle xyz=90 and xysquare + yz square=289 . Find xz

Answer 1

Answer:

The value of XZ is 17.

Step-by-step explanation:

It is provided that in triangle XYZ the angle ∠XYZ = 90°.

This implies that XYZ is a right-angled triangle.

Since XYZ is a right-angled triangle using Pythagoras theorem,

$XZ^{2}=XY^{2}+YZ^{2}$

Given: $XY^{2}+YZ^{2}=289$

Determine the value of XZ as follows:

$XZ^{2}=XY^{2}+YZ^{2}\\=289\\XZ=\sqrt{289}\\=\pm 17$

Since the length of a side cannot be negative, the value of XZ is 17.

Answer 2

Answer:

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Step-by-step explanation:

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