In ∆XYZ, P is a point on side YZ. If T is the midpoint of XP, prove that, ar(TYZ)=1/2 ar(XYZ)
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Area of XYZ = YZ x XP/2
Area of TYZ = YZ x TP /2 ...........1
XP = 2TP
Area of XYZ = YZ x 2TP/ 2
= YZ x TP .............2
From 1 and 2
Area of TYZ = 1/2 Area of XYZ
Area of TYZ = YZ x TP /2 ...........1
XP = 2TP
Area of XYZ = YZ x 2TP/ 2
= YZ x TP .............2
From 1 and 2
Area of TYZ = 1/2 Area of XYZ
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