Question

in ∆xyz,right angle is at y,yz=x,and xz=2x then determine angle yxz and angle yzx

Answer 1

go this way use basics of trigo

Answer 2

Answer:

Given that:-

• In triangle XYX,right angles is at Y ,YZ= x and XZ = 2x .

To find:-

• angle yxz and angle yzx.

$\huge\sf{Solution:-}$

Sin x = opposite side of x/hypotenuse

⇒ x/2x = 1/2

Sin x = 1/2 = Sin 30°

⇒ x = 30° or ∠ YXZ = 30°

Cos Z = Adjacent side of z/hypotenuse

⇒ x/2x = 1/2 

⇒ Cos Z = 1/2 = Cos 60°

Answer :- Z = 60° = ∠ YZX = 60°