In ΔXYZ, ∠X = 100 and XW bisects ∠X and XW ⊥ YZ. Find ∠Y.
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- xw bisects yz, thus angle xwy= 90°
- angle x = 100° degree and xw bisects angle a( given),so angle yxw = 50°
- now in triangle xwy
- angle y+ angle xwy + angle yxw= 180°( angle sum of triangle)
- angle y+ 90°+50°=180°
- angle y = 180°-140°=40° answer
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