In XYZ, XP is median of XYZ. XP = 9cm XY + XZ = 290 cm. Find YZ.
a. 17 cm b. 16 cm c. 15 cm d. 14 cm
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1
Answer:
In △XQP and △XYZ,
∠XQP=∠XYZ=90
∘
∠QXP=∠YXZ (Common angle)
∴△XQP∼△XYZ
XZ
XP
=
XY
XQ
(By properties of similar triangle)
⇒
24cm
4cm
=
16cm
XQ
⇒XQ=
6
16
cm
⇒XQ=
3
8
cm
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