In ∆XYZ ,XY>XZ and P is any point on the side YZ. Prove that XY>XP
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XY > XP
Hence prove
Step-by-step explanation:
In ∆XYZ ,
XY > XZ
∴ ∠XZY > ∠XYZ ( ∵ If opposite sides of triangle is greater their corresponding angle is greater)
∠XPY = ∠PXZ + ∠XZP ( ∵ Exterior angle of a triangle )
So, ∠XPY > ∠XZP
But ∠XZY > ∠XYZ
Therefore, ∠XPY > ∠XYZ ( ∵ ∠XZP = ∠XZY )
In ∆XYP ,
∠XPY > ∠XYZ ( Prove above )
∴ XY > XP ( ∵ Side is greater if their opposite angles are greater)
Hence prove
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https://brainly.in/question/14705389
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