Question

In ∆XYZ ,XY>XZ and P is any point on the side YZ. Prove that XY>XP​

Answer 1

Answer:

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Answer 2

XY > XP    

Hence prove

Step-by-step explanation:

In ∆XYZ ,

XY > XZ

∴ ∠XZY > ∠XYZ    ( ∵ If opposite sides of triangle is greater their corresponding angle is greater)

∠XPY = ∠PXZ + ∠XZP  ( ∵ Exterior angle of a triangle )

So, ∠XPY > ∠XZP

But ∠XZY > ∠XYZ

Therefore,  ∠XPY > ∠XYZ              ( ∵ ∠XZP = ∠XZY )

In ∆XYP ,

∠XPY > ∠XYZ       ( Prove above )

∴ XY > XP     ( ∵ Side is greater if their opposite angles are greater)

Hence prove

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