In ∆ XYZ , xy=xz = 29 cm and yz =40cm . Find area (XYZ)
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Answer:
∠XZY=90
∘
XY
2
=XZ
2
+YZ
2
(Using Pythagoras Theorem)
(26)
2
=(24)
2
+YZ
2
YZ
2
=676−576
YZ=10cm
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