Question

In YDSE, d = 2mm, D = 2m, and λ=500nm. If intensities of the two slits are I and 9I , then find the intensity at y = 1/6mm

Answer 1

Explanation:

Δx =   2 /6mmx  2mm

    =  1/6 M unit

Ф = 2π Δx/λ

  = 2π /6 Mx500nm

  =2π/3

I = 1 + 9 + 2√ 1X 9 X cos2π/3

 = 7 I

Answer 2

Answer:

Net Intensity= 7I

Explanation:

Hey there,

Since we know that

=> path diff.(x)=yd/D

Also,

=>ø/x =2(pi)/lambda

Using these we find phase diff.(ø) and find net intensity

For detailed solution refer tye attachement below!

Hope this answer helped you✌ :)