Physics, asked by Nareshk8812, 11 hours ago

In ydse the intensity of central bright fringe is 8mw/m2. What will be the intensity at /6 path difference?

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Answered by aanjnejasinghpatel8j
1

Answer:

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In YDSE The intensity of central bright fringe is 8mW/m

2

. What will be the intensity at λ/6 path difference?

Medium

Solution

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Correct option is

B

6mW/m

2

Given that,

Intensity of central bright fringe I

0

=8mW/m

2

We know that,

I=I

0

cos

2

(

2

ϕ

)

I=8cos

2

(

2

ϕ

)

Now,

Phase difference =

λ

x path difference

ϕ=

λ

×

6

λ

ϕ=

3

π

Now, the intensity is

I=8×cos

2

(

6

π

)

I=8×

2

3

×

2

3

I=6mW/m

2

Hence, the intensity is 6mW/m

2

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