Question

In YDSE the wavelength of light used is 500 nm and slit width is 0.05 mm. then the angular fringe width will be​

Answer 1

In YDSE the wavelength of light used is 500 nm and slit width is 0.05 mm.

To find : The angular fringe width will be....

solution : using formula, angular fringe width, $\beta=\frac{\lambda}{d}$

where λ is wavelength of monochromatic light used in YDSE and d is slit width.

here slit width, d = 0.05 mm = 5 × 10¯⁵ m

and wavelength, λ = 500 nm = 5 × 10¯7 m

now β = (5 × 10¯7)/(5 × 10¯⁵) = 1/100 rad

we know, π rad = 180°

so, 1/100 rad = (180/100π)° = 0.57°

Therefore the angular fringe width is 0.57°