Math, asked by anantg250, 11 months ago

In yet another demonetization, the government wants to issue exactly X denominations of notes (in whole numbers) such that by using no more than 3 notes which may be of the same value, a citizen can pay all amounts ranging from 1 to 36 rupees both inclusive. For the minimum value of X for which it is possible, find the sum of the values of these denominations?​

Answers

Answered by amitnrw
0

Denominations of note can be  1  , 4   & 7  , X = 3 , Sum of value of denominations = 1 + 4 + 7  = 12

Step-by-step explanation:

Dnominatons of note can be  

1  , 4   & 7

X = 3

Sum of value of denominatons = 1 + 4 + 7  = 12

1  = 1

2  = 1 + 1

3  = 1 + 1 + 1

4 = 4

5 = 4 + 1

6 = 4 + 1 + 1

7 = 4 + 1 + 1 + 1

8 = 4+4

9 = 4+4 + 1

10 = 4+4 + 1 + 1

11 = 4+4 + 1 + 1 + 1

12 = 4+4+4

13 = 4+4+4 + 1

14 = 4+ 4+4 + 1 + 1

15 = 4+ 4+ 4 + 1 + 1 + 1

16 = 7 + 4+4 + 1

17 = 7 + 4+4 + 1 + 1

18 = 7 + 4+4 + 1 + 1 + 1

19 = 7 + 4+4+4

20 = 7 + 4+4+4 + 1

21 = 7 + 4+ 4+4 + 1 + 1

22 = 7 + 4+ 4+ 4 + 1 + 1 + 1

23 = 7 + 7 +4+4 + 1

24 = 7 + 7 +4+4 + 1 + 1

25 = 7 + 7 +4+4 + 1 + 1 + 1

26 = 7 + 7 +4+4+4

27 = 7 +7 +4+4+4 + 1

28 = 7 + 7 +4+ 4+4 + 1 + 1

29 = 7 + 7 +4+ 4+ 4 + 1 + 1 + 1

30 = 7 + 7+ 7 +4+4 + 1

31 = 7 + 7+ 7 +4+4 + 1 + 1

32 = 7 + 7+ 7 +4+4 + 1 + 1 + 1

33 = 7 + 7+ 7 +4+4+4

34 = 7 +7+ 7 +4+4+4 + 1

35 = 7 + 7+ 7 +4+ 4+4 + 1 + 1

36 = 7 + 7+ 7 +4+ 4+ 4 + 1 + 1 + 1

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