Question

In young double slit experiment slit separation x=0.05cm, distance between screen and slit D=200cm, fringe separation x=0.13cm,the wavelength of light is

Answer 1

≈ WAVE ≈ OPTICS ≈ YDSE

Explanation:

Given ;

★ D = 200cm = 2m

★ d = 0.05 cm = 5 × 10-² m

★ y ( Fringe separation ) = 0.13 cm = 13 × 10-² m

★ lamda ( wavelength ) = ???

Now ; using width formula ....

★ Y = lambda × D / d

» Lambda = (Y × d ) / D

= (13 × 10-² × 5 × 10-² ) / 2

= 65 × 10-⁴ / 2

= 32.5 × 10-⁴

«★» lambda ≈ 32500000 Å

< ..... HENCE :- WAVELENGTH IS MUCH SMALLER .... FRINGES WOULDN'T BE PRESENT ....>