Question

In Young Double Slit Experiment, When Wavelength Used Is 6000 Ao And The Screen Is 40 cm From The Slits , The Fringes Are 0.012 cm Wide. What Is The Distance Between The Slits?

Answer 1

Solution "

Given :

✏ Wavelength of light = 6000 A°

✏ Distance between screen and slits = 40 cm

✏ Width of fringes = 0.012 cm

To Find :

✏ Distance between the slits.

Formula :

✏ Formula of width of fringe in YDSE is given by

$\star \: \boxed{ \bold{ \sf{ \pink{ \beta = \frac{ \lambda \: D}{d}}}}} \: \star$

Terms indication :

✏ β denoes width of fringes

✏ $\lambda$ denotes wavelength of light

✏ D denotes distance between screen and slits

✏ d denotes distance between the slits

Calculation :

$\rightarrow \sf \: \beta = \frac{ \lambda \: D}{d} \\ \\ \rightarrow \sf \: d = \frac{ \lambda \: D}{ \beta} = \frac{6 \times {10}^{ - 5} \times 40 }{0.012} \\ \\ \rightarrow \: \boxed{ \sf{ \red{d = 0.2 \: cm = 2 \: mm}}} \: \star$