Physics, asked by Priag32471, 9 months ago

In Young Double Slit Experiment, When Wavelength Used Is 6000 Ao And The Screen Is 40 cm From The Slits , The Fringes Are 0.012 cm Wide. What Is The Distance Between The Slits?

Answers

Answered by Anonymous
2

Solution "

Given :

✏ Wavelength of light = 6000 A°

✏ Distance between screen and slits = 40 cm

✏ Width of fringes = 0.012 cm

To Find :

✏ Distance between the slits.

Formula :

✏ Formula of width of fringe in YDSE is given by

 \star \:   \boxed{ \bold{ \sf{ \pink{ \beta =  \frac{ \lambda \: D}{d}}}}}  \:  \star

Terms indication :

✏ β denoes width of fringes

\lambda denotes wavelength of light

✏ D denotes distance between screen and slits

✏ d denotes distance between the slits

Calculation :

 \rightarrow \sf \:  \beta =  \frac{ \lambda \: D}{d}  \\  \\  \rightarrow \sf \: d =  \frac{ \lambda \: D}{ \beta}  =  \frac{6 \times  {10}^{ - 5} \times 40 }{0.012}  \\  \\  \rightarrow \:  \boxed{ \sf{ \red{d = 0.2 \: cm = 2 \: mm}}} \:  \star

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