In young's double-hole experiment, a thin mica sheet (n = 1.5) is introduced in the path of one of the beams. If the central fringe gets shifted by 0.2 cm, calculate the thick- ness of the mica sheet. Assume d = 0.1 cm and d = 50 cm.
Answers
Answer:
✅ THICKNESS OF MICA SHEET ( t ) = 0.8 MICROMETER / 0.8 μ m ✅
Explanation:
★ WAVE OPTICS ★
★ Given ;
[ YDSE SETUP WAS INSERTED WITH MICA SHEET AT ONE SLIT , DUE TO THIS INTERFERENCE PATTERN CHANGES ] .
» Refractive Index of Mica Sheet ( μ ) = 1.5
» Shift in Central Maxima ( Y ) = 0.2 cm
» Distance between Slits ( d ) = 0.1 cm
» Distance between Screen and Slit ( D ) = 50 cm
★ THICKNESS OF THE MICA SHEET ( t ) = ????
_________ [ BY USING FORMULA ] _____
⏩ ⏩ [ " Y = ( μ - 1 ) × t × D / d " ] ⏪ ⏪
★ Y = [ ( 1.5 - 1 ) × t × 50 cm ] / 0.1 cm
» 0.2 × 10-³ = [ ( 0.5 ) × t × 0.5 ] / 10-³
» t = [ 2 × 10-⁴ × 10-³ ] / 0.25
» t = 8 × 10^-7
★ » t = 0.8 × 10^-6 m « ★
————————— [ OR ] ————————
★ » t = 0.8 μ m / 0.8 micrometer « ★
________________________________________
ANSWER :- Thickness of the Mica Sheet having Refractive Index of 1.5 is ;
♣ Thickness ( t ) = 0.8 Micrometer /
0.8 μ m ♥
[ NOTE :- WAVELENGTH REMAINS INDEPENDENT OF ANY INSERTION OF GLASS SLAB ]