In Young's double slit experiment fringe width of pattern for light of wavelength is 600nm is 0.4mm. what will be the fringe width if entire apparatus is placed in water of RI 4/3.
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Fringe width β=
d
Dλ
When immersed in water, the wavelength becomes λ ′ = μλ
Thus the new fringe width =β ′ =β× λλ ′
=β× μ1
=1.5mm
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