Question

In Young’s double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes :

Answer 1

Answer:

fringe width = lamda×D/d

Explanation:

D is the distance of the screen from coherent source.

d is the separation between the slits.

lamda is wavelength.

hence when value of d is halved and D is doubled, the fringe width increases four times the original value.