Question

In Young's double slit experiment if the wavelength of light is doubled then fringe widths will be

Answer 1

The fringe widths will be doubled.

Explanation:

The distance between fringes (fringe widths) in Young's double slit experiment is given by

$Y=\frac{X\lambda}{d}$               (1)

Here, X is the distance between screen and slit, d is the distance between slits and $\lambda$ is the wavelength of light.

As per question, wavelength of light is doubled, then above formula becomes

$Y`=\frac{X(2\lambda)}{d}$

Therefore, from equation (1),

$Y`=2Y$

Thus, the fringe widths will be 2 times.

#Learn More: Young's double slit experiment.

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Answer 2

Answer:

So here if the wavelength of light is double then the fringe width must be double of initial value