Question

In young's double-slit experiment, suppose the separation between the two slits is d=0.320 mm. if a beam of 500-nm light strikes the slits and produces an interference pattern. how many maxima will there be in the angular range −45.0°< θ < 45.0°?

Answer 1

I think the number of maxima will be 247 maybe..

Answer 2

dsinθ=nλ

sinθ×32×10

−5

=

n×500×10

−9

sinθ=

3200

n5

at θ=30

o

2

1

=

3200

n5

⟹n=

5

1600

=320

So there will be 320+ve,320−ve,1 central

Total =641