Question

In young's double slit experiment the distance between two sources is 0.1 millimetre the distance of the screen from the sources 20cm wavelength of the light used is 5460 armstrong the angular position of the first dark fringe is nearly

Answer 1

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Answer 2

Answer:

The angular position of the first dark fringe is 0.00546

Explanation:

Given that,

Distance between two sources = 0.1 mm

Distance of the screen from the sources = 20 cm

Wave length$\lambda = 5460\times10^{-10}$

The formula of position is given by

$y_{n}=\dfrac{(2n-1)\lambda\times D}{d}$

For first dark fringe

n = 1

$y_{1}=\dfrac{(2-1)\times5460\times10^{-10}\times20\times10^{-2}}{0.1\times10^{-3}}$

$y=0.001092$

The angular position of the first dark fringe is

$\theta=\dfrac{y}{D}$

Put the value into the formula

$\theta=\dfrac{0.001092}{20\times10^{-2}}$

$\theta=0.00546$

Hence, The angular position of the first dark fringe is 0.00546