Question

In young's double slit experiment the maximum intensity is i when one slit is closed the intensity becomes:

Answer 1

Explanation:

Intensity is proportional to square of amplitude of wave. If amplitude of wave of each source is a, then after superposition intensity is prportional to (2a)2 i.e., 4a2 . If one source is closed, there is no superposition, hence intensity is proportional to a2. Hence I = 4 I' is the correct answer

Answer 2

Answer:

Lower is the answer...........

Explanation:

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