Physics, asked by berasaikat90, 11 months ago

In Young’s Double Slit Experiment, the separation of the slits is 1.9mm & the fringe spacing is 0.31mm at a distance of 1m from the slit. Calculate the wavelength of light.​

Answers

Answered by satkarchunny
3

Answer:

In a Young’s double slit experiment, slits are separated by 0.5 mm, and the screen is placed 150 cm away.  A beam of light consisting of two wavelengths, 650 nm and 520 nm, is used to obtain interference fringes on the screen.  The least distance from the common central maximum to the point where the bright fringes due to both the wavelengths coincide is :

 

Option 1)  1.56 mm   Option 2)  7.8 mm   Option 3)  9.75 mm   Option 4) 15.6 mm

Explanation:

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