Question

In young’s double slit experiment the slits are 0.5 mm apart and interferance is observed on a screen placed at a distance of 100 cm from the slits. It is found that the 9th bright fringe is at a distance 8.835mm from the second dark fringe from the centre of the fringe pattern. Find the wavelength of light used.

Answer 1

In Young's double slit experiment, the slits are 0.5 mm apart and interference is observed on a screen placed at a distance of 100 cm from the slits. It is found that the 9th bright fringe is at a distance 8.835 mm from the second dark fringe from the centre of the fringe pattern. Find the wavelength of light used.

Wave Optics | 188741 - In the YDSE the slits are 0.5mm apart and ...

D = 100 cm = 1 m. X9 – X′2 = 8.835 mm [Assuming both bright and dark fringes are on same side of centre of fringe ... Since distance of nth bright band

Answer 2

5890A would be the wavelength of light

Explanation:

9th  bright fringe = 9λD/d

2nd  dark fringe = 3λD/2d

So,

9λD/d - 3λD/2d = 8.835× $10^{-3}$m

15λD/2d = 8.835× $10^{-3}$m

λ = 8.835× $10^{-3}$ × 2 × 0.5 × $10^{-3}$/(15 ×  1)

= 0.589 × $10^{-6}$

= 5890A

Learn more: wavelength

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