Question

In young's double slit experiment the two slits are illuminated by light of wavelength 5890a and the distance between the fringes obtained on the screen s0.2 the whole apparatus is immersed in water, then find out angular fringe cale will sol.: width, (refractive index of water =

Answer 1

Answer:

The angular width of the fringe formed on the screen is

$\theta = 2.21 \times 10^{-3} rad$

Explanation:

The angular width of the fringe on the screen is given as

$\theta = \frac{\lambda}{a}$

here we know

$\lambda = 5890 A^o$

$a = 0.2 mm$(slit width)

so we have to find the angular width when whole apparatus is immersed in water

$\theta = \frac{\lambda/\mu}{a}$

so we have

$\theta = \frac{5890\times 10^{-10}}{(0.2 \times 10^{-3})(1.33)}$

$\theta = 2.21 \times 10^{-3} rad$

#Learn

Topic : Angular fringe width

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