Question

in young's double slit experiment using light wavelength 5000Å what phase difference correspondence to the 11 darck fring the centre of the inter reference pattern​

Answer 1

For Dark Fringe, its Path Difference will be :

$\boxed{\bold{\sf{Path \ Difference \ (\Delta x)=(2n-1)\frac{\lambda}{2}}}}$

The equation to find the Phase Difference :

$\boxed{\bold{\sf{Phase \ Difference=(\Delta x)\times \frac{2\pi}{\lambda}}}}$

Applying the values to the equation :

$\sf{\implies Phase \ Difference=(2n-1)\dfrac{\lambda}{2} \times \dfrac{2\pi}{\lambda}}$

Here, 2&2   &   λ&λ cuts off.

$\sf{\implies Phase \ Difference=(2n-1)\pi}$

Here, n = 11th fringe

So,

$\sf{\implies Phase \ Difference=(2\times 11-1)\pi}$

$\sf{\implies Phase \ Difference=(22-1)\pi}$

$\sf{\implies Phase \ Difference=21\pi}$

$\huge{\boxed{\bold{\sf{\therefore Phase \ Difference=21\pi}}}}$

Answer 2

Answer:

above answer is correct

Explanation:

answer is 21 pi

Above answer is correct