Question

In young's double slit experiment what happens if width of slits are doubled

Answer 1

Explanation:

It's coherent enough to produce the interferencepattern. If the sunlight is passed through a single slitbefore the double slits, you get light that's significantly more coherent. ... But you can only see visible light in theinterference pattern, and that is relatively small range of wavelengths.

Answer 2

Answer:

The fringe width will get doubled.

Explanation:

We have,

β = λd/D  

Where β = fringe width

λ = wavelength of wave.

d= distance between slits

D= Distance between screen and slits.

Now,

When $\\\tt d_{new}$= 2d

$\\\tt \beta_{new} =\dfrac{ \lambda (d_{new} ) }{D} =\dfrac{2 \lambda (d ) }{D}\\\implies \beta_{new} = 2 \beta$

Therefore the fringe width will be doubled.