Question

In Young's double slit experiment with light of wavelength 450nm has two slits 2mm apart. what will be the fringe width on the screen at a distance of 0.5m. Also find the distance between 7th bright fringe and 3rd bright fringe.​

Answer 1

Given : D=1 m, λ=650×10

−9

m, d=1 mm=10

−3

m

Distance of third dark fringe from centre of pattern

x

1

​

=(3−

2

1

​

)

d

Dλ

​

=

2

5

​

×

1×10

−3

1×650×10

−9

​

=1.62mm

Distance of fifth bright fringe from centre of pattern

x

2

​

=5

d

Dλ

​

=3.24mm

∴ Required distance Δx=x

2

​

−x

1

​

Δx=3.24−1.62=1.62mm

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