Question

In Young's experiment the amplitude ratio of
interfering waves is 3 : 2. Ratio of intensities
between the bright and dark fringes is
(1) 9/4
(2) 25
(3) 3/2
(4) 5

Answer 1

Answer:

2. 25

Explanation:

its correct answer

Answer 2

The ratio of intensities is 9:4.

(1) is correct option.

Explanation:

Given that,

Ratio of amplitude = 3:2

We know that,

The intensity of fringe is directly proportional to the square of amplitude of wave.

$I\propto A^2$

We need to calculate the ratio of intensities

Using formula of intensities

$\dfrac{I_{b}}{I_{d}}=\dfrac{A_{b}^2}{A_{d}^2}$

Put the value into the formula

$\dfrac{I_{b}}{I_{d}}=\dfrac{9}{4}$

Hence, The ratio of intensities is 9:4.

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Topic : Young's experiment

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