Question

In Young’s experiment, the distance between two slits is 1 mm and the distance between two consecutive bright fringes is 0.03 cm. Now, on displacing the screen away from the slits by 50 cm, the distance between two consecutive dark fringes is doubled. Find the wavelength of light used. [Ans: 6000 Å]

Answer 1

Answer:

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Explanation:

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Answer 2

Given:

d = 1 mm

Fringe width = $0.03$ cm

To find:

We need to the find the value of wavelength.

Solution:

We know that, fringe width is given by the formula, $\frac{D}{1}\frac{\lambda}{d}$.

So,

$\frac{D}{1}\frac{\lambda}{d}= 0.03$.....Equation 1

According to the question, screen is displaced 50 cm away.

Distance between two consecutive dark fringe = Distance between two consecutive dark fringe.

Now,

$\frac{\((D+50)}{\lambda}{d}= 0.06$ .....Equation 2

Now, divide equation 1 and equation 2, we get

D = 50 cm

Now, put the value of D in equation 1, we get

$\lambda=$ 6000 $A^{0}$.