Question

In Younge's double slit
experiment if slit widths are in ratio 1:2
then their intensities are in ratio
01:2
1:3
01:4
1:9​

Answer 1

Answer:

Intensity of a fringe is directly proportional to width of the slits i.e I∝W

∴

I

1

I

2

=

W

1

W

2

I

1

I

2

=

9

1

⟹I

1

=9I

2

Maximum intensity I

max

=(

I

1

+

I

2

)

2

∴ I

max

=(

9I

2

+

I

2

)

2

=(3

I

2

+

I

2

)

2

=(4

I

2

)

2

⟹ I

max

=16I

2

Minimum intensity I

min

=(

I

1

−

I

2

)

2

∴ I

min

=(

9I

2

−

I

2

)

2

=(3

I

2

−

I

2

)

2

=(2

I

2

)

2

⟹ I

min

=4I

2

∴

I

max

I

min

=

16I

2

4I

2

=

4

1