In (z +a) (z+b) if a=b= 2 then the expression becomes
a) z² +4
(b) (z+4)²
(c) z² + 2
(d) ( z+ 2)²
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Answer:
my answer is (a)
Step-by-step explanation:
(z+a) (z+b)
(z+2) (z+2)
we known that when the sign is is not the middle of the two bracket
then we put a multiply sing
(z+2)×(z+2)
=z²+2z+2z+4
=z²+4
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