in zorks, blue tall feathers are dominant and red ones are recessive. also long toes are dominant and short toes are recessive. cross a homozygous blue- tailed, heterozygous long-toed zork (male) with a homozygous red-tailed, short-toed zork (female)
Answers
Answered by
0
Dear...
first of all
I would assign
F(Dominant)and f(recessive) =feathers or for tails
T(Dominant) and t (recessive )=Toes
Now The answer is=
FFTt(Male)×fftt(female)=
_FfTt and
Fftt
first of all
I would assign
F(Dominant)and f(recessive) =feathers or for tails
T(Dominant) and t (recessive )=Toes
Now The answer is=
FFTt(Male)×fftt(female)=
_FfTt and
Fftt
Similar questions