Question

inA B C, angle B is a right angled triangle write sin A tan C cos A​

Answer 1

Step-by-step explanation:

In right angled Δ ABC,

Given, tanC=3

We know that, tanθ=adjacent side to∠θopposite side to∠θ

∴AB=3 and AC=1

From Pythagoras theorem,

BC2=AB2+AC2

BC2=(3)2+12

BC2=3+1=4

BC=2

sinθ=hypotenuseopposite side to∠θ

cosθ=hypotenuseadjacent side to∠θ

sinB=BCAC=21

cosB=BCAB=23