Ina family of three children the probability of having at least one boy is
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See the sample space is
B B B B B G
G G B G G G
B G B B G G
G B B G B G
{ Here GBB, BBG and so on are not the same events as The girl or boy may be elder or younger }
P ( E) = no. of favourable outcome / Total no. of outcome
P ( at least one boy) = 7 / 8
Hope the solution is clear to you!!
Answered by
1
The outcomes are GGG, BBB, GBB,GGB, GBG, BGG, BBG, BGB,
Total outcomes =8
Probability of having at least one boy=7/8
hope this helps you.
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