Question

Ina fraction sum of numerator and denominator is equal to 60 if 2 is added the numerator and 2 is subtracted from denominator.the value of fraction becomes 1/3 find the fraction

Answer 1

$\huge\tt{\bold{\underline{\underline{Question᎓}}}}$

In a fraction sum of numerator and denominator is equal to 60 if 2 is added the numerator and 2 is subtracted from denominator.the value of fraction becomes 1/3 find the fraction

$\huge\tt{\bold{\underline{\underline{Answer᎓}}}}$

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Let the fraction be x/y

Given :sum of numerator and the denominator is =60

=>x+y=60

$\bold{\boxed{\red{x=60-y}}}$

According to the question:

$= > \frac{x + 2}{y - 2} = \frac{1}{3}$

$= > 3x + 6 = y - 2$

$= > 3x - y = - 8$

$= > 3(60 - y) - y = - 8$

$= > 180 - 3y - y = - 8$

$= > 180 - 4y = - 8$

$= > - 4y = - 8 - 180$

$= > - 4y = - 184$

$= > y = \frac{184}{4} = 46$

$\bold{\green{y = 46}}$

$\bold{ = > X= 60 - y = 60 - 46 = 14}$

$\bold{\red{x = 14}}$

$\bold{\boxed{Fraction = \frac{x}{y} = \frac{14}{46} \: or \: \frac{7}{23}} }$

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