Ina right angle ∆ABC, angle B=90⁰, AC=30 ,AB= 4a & BC= 3a, then the value of a is _______
(A) 6 (B) 12 (C)18 (D) 24
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In right-angled ∆ ABC, ∟B=90⁰. ∆ ABC is in the first and second quadrant on the graph paper. The coordinates of the points A and C are (2,5) and (-2,3). How do you find the possible pairs of coordinates of B?
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Sreeram Vipparthy
, M Tech from Andhra University College of Engineering (2001)
Answered 1 year ago · Author has 83 answers and 18.1K answer views
Hope you know that all the triangles can be inscribed in corresponding circles i.e. any given triangle can be inscribed in exactly one circle. You might have constructed circum-circles, inner-circles for a given triangle, in your geometry lessons.
Of which, a right angled triangle, such as the one you have mentioned in your question, has a special property. The hypotenuse of a right angled triangle is the diameter of the circum-circle. So, answer for your question would not be a unique B, instead it is the locus of the circle that encircles your triangle, ∆ ABC, where B can lie anywhere on the circumference.
I think you can compute the locus of the point B. Our friends have worked out and shared images of hand-written notes for you. If you want a LaTeX note, I give it here.
Step-by-step explanation:
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